Using some trigonometry, the height h is determined.
h = l - l cos (theta) where l is the length of the string (say 10 meters) and the starting angle theta (60 °).
In this pendulum system, the height h is equal to l - l cos (theta).
The energy is conserved, so the kinetic energy E c of the ball moving at the impact point is equal to the potential energy we have calculated (the air friction is neglected).
http://droidartists.jimdo.com/2014/07/28/fossilized-remains-of-primitive-feathers/
http://androidapp-games.weebly.com/blog/the-superterres-could-be-poorer-than-expected-water
http://androidstars.weebly.com/blog/the-evolution-of-galaxy-populations
E c = ½ mv 2 = mg (l - l cos (theta))
This allows to derive the speed v at which the ball hits the wall.
v = sqrt (2 gl (1-cos (theta))) = sqrt (2 x 9.81 x 10 (1 - cos (60 °)) is v = 9.904 m s -1
h = l - l cos (theta) where l is the length of the string (say 10 meters) and the starting angle theta (60 °).
In this pendulum system, the height h is equal to l - l cos (theta).
The energy is conserved, so the kinetic energy E c of the ball moving at the impact point is equal to the potential energy we have calculated (the air friction is neglected).
http://droidartists.jimdo.com/2014/07/28/fossilized-remains-of-primitive-feathers/
http://androidapp-games.weebly.com/blog/the-superterres-could-be-poorer-than-expected-water
http://androidstars.weebly.com/blog/the-evolution-of-galaxy-populations
E c = ½ mv 2 = mg (l - l cos (theta))
This allows to derive the speed v at which the ball hits the wall.
v = sqrt (2 gl (1-cos (theta))) = sqrt (2 x 9.81 x 10 (1 - cos (60 °)) is v = 9.904 m s -1
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