Using some trigonometry, the height h is determined.

h = l - l cos (theta) where l is the length of the string (say 10 meters) and the starting angle theta (60 °).

In this pendulum system, the height h is equal to l - l cos (theta).

The energy is conserved, so the kinetic energy E c of the ball moving at the impact point is equal to the potential energy we have calculated (the air friction is neglected).

http://droidartists.jimdo.com/2014/07/28/fossilized-remains-of-primitive-feathers/

http://androidapp-games.weebly.com/blog/the-superterres-could-be-poorer-than-expected-water

http://androidstars.weebly.com/blog/the-evolution-of-galaxy-populations

E c = ½ mv 2 = mg (l - l cos (theta))

This allows to derive the speed v at which the ball hits the wall.

v = sqrt (2 gl (1-cos (theta))) = sqrt (2 x 9.81 x 10 (1 - cos (60 °)) is v = 9.904 m s -1

h = l - l cos (theta) where l is the length of the string (say 10 meters) and the starting angle theta (60 °).

In this pendulum system, the height h is equal to l - l cos (theta).

The energy is conserved, so the kinetic energy E c of the ball moving at the impact point is equal to the potential energy we have calculated (the air friction is neglected).

http://droidartists.jimdo.com/2014/07/28/fossilized-remains-of-primitive-feathers/

http://androidapp-games.weebly.com/blog/the-superterres-could-be-poorer-than-expected-water

http://androidstars.weebly.com/blog/the-evolution-of-galaxy-populations

E c = ½ mv 2 = mg (l - l cos (theta))

This allows to derive the speed v at which the ball hits the wall.

v = sqrt (2 gl (1-cos (theta))) = sqrt (2 x 9.81 x 10 (1 - cos (60 °)) is v = 9.904 m s -1

## No comments:

## Post a Comment